The way of function interacts with its arguments

 Consider the below example.

Example - 1

The output is given below.

Here, changing the parameter's value doesn't propagate outside the function.

This also means that a function receives the argument's value, not the argument itself. This is true for scalars.

Let's apply this theory for lists.

Example - 2

The output is,

Example - 3

The output is,

Explanation:-

1. If the argument is a list, then changing the value of the corresponding parameter doesn't affect the list (But variables containing lists are stored in a different way than scalars)
2. But if we change a list identified by the parameter (not the parameter), the list will reflect the change.